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docs(lvl09): adding the english readme

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Raphael 2026-01-29 12:53:53 +01:00
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rparodi/level09/README.md
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@ -1,4 +1,4 @@
Lors de mon arriver sur le level09 je remarque un fichier level09 When arriving on level09 I notice a file level09.
```bash ```bash
ls -l ls -l
@ -7,13 +7,13 @@ total 12
----r--r-- 1 flag09 level09 26 Mar 5 2016 token ----r--r-- 1 flag09 level09 26 Mar 5 2016 token
``` ```
Token a plein de character illisible Token has a lot of unreadable characters.
```bash ```bash
cat token cat token
f4kmm6p|=<3D>p<EFBFBD>n<EFBFBD><6E>DB<44>Du{<7B><> f4kmm6p|=<3D>p<EFBFBD>n<EFBFBD><6E>DB<44>Du{<7B><>
``` ```
Afin de recuperer les characteres In order to recover the characters:
```bash ```bash
cat token | hexdump -C cat token | hexdump -C
00000000 66 34 6b 6d 6d 36 70 7c 3d 82 7f 70 82 6e 83 82 |f4kmm6p|=..p.n..| 00000000 66 34 6b 6d 6d 36 70 7c 3d 82 7f 70 82 6e 83 82 |f4kmm6p|=..p.n..|
@ -21,7 +21,7 @@ cat token | hexdump -C
0000001a 0000001a
``` ```
Je pense que le binaire est donc le programme qui permet "d'encrypter" le fichier si c'est correct alors l'algorithme suivi est donc str\[i] + i I think that the binary is therefore the program which allows to “encrypt” the file. If this is correct then the algorithm followed is therefore str[i] + i.
```bash ```bash
./level09 aaa ./level09 aaa
@ -36,7 +36,8 @@ a + 2 = c
f3iji1ju5yuevaus41q1afiuq f3iji1ju5yuevaus41q1afiuq
``` ```
Je tente de me connect sur flag09 et ca marche et j'obtient donc le flag: I try to connect on flag09 and it works and I therefore obtain the flag:
```bash ```bash
getflag getflag
Check flag.Here is your token : s5cajpm8ev6xhw998prwg728z Check flag.Here is your token : s5cajpm8ev6xhw998prwg728z